(4y-3)=(2y+15)

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Solution for (4y-3)=(2y+15) equation: 



(4y-3)=(2y+15)

We move all terms to the left:

(4y-3)-((2y+15))=0

We get rid of parentheses

4y-((2y+15))-3=0



We calculate terms in parentheses: -((2y+15)), so:

(2y+15)

We get rid of parentheses

2y+15

Back to the equation:

-(2y+15)



We get rid of parentheses

4y-2y-15-3=0

We add all the numbers together, and all the variables

2y-18=0

We move all terms containing y to the left, all other terms to the right

2y=18

y=18/2

y=9

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