(4y-3)/3y=2

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Solution for (4y-3)/3y=2 equation: 



(4y-3)/3y=2

We move all terms to the left:

(4y-3)/3y-(2)=0



Domain of the equation: 3y!=0

y!=0/3

y!=0

y∈R



We multiply all the terms by the denominator


(4y-3)-2*3y=0

Wy multiply elements

(4y-3)-6y=0

We get rid of parentheses

4y-6y-3=0

We add all the numbers together, and all the variables

-2y-3=0

We move all terms containing y to the left, all other terms to the right

-2y=3

y=3/-2

y=-1+1/2

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