(4y-3)+(3y+1)=180

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Solution for (4y-3)+(3y+1)=180 equation: 



(4y-3)+(3y+1)=180

We move all terms to the left:

(4y-3)+(3y+1)-(180)=0

We get rid of parentheses

4y+3y-3+1-180=0

We add all the numbers together, and all the variables

7y-182=0

We move all terms containing y to the left, all other terms to the right

7y=182

y=182/7

y=26

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