(4y-27)=(81+y)

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Solution for (4y-27)=(81+y) equation: 



(4y-27)=(81+y)

We move all terms to the left:

(4y-27)-((81+y))=0

We add all the numbers together, and all the variables

(4y-27)-((y+81))=0

We get rid of parentheses

4y-((y+81))-27=0



We calculate terms in parentheses: -((y+81)), so:

(y+81)

We get rid of parentheses

y+81

Back to the equation:

-(y+81)



We get rid of parentheses

4y-y-81-27=0

We add all the numbers together, and all the variables

3y-108=0

We move all terms containing y to the left, all other terms to the right

3y=108

y=108/3

y=36

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