(4y-2)-(2y+3)+(-2+4)=0

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Solution for (4y-2)-(2y+3)+(-2+4)=0 equation:


Simplifying
(4y + -2) + -1(2y + 3) + (-2 + 4) = 0

Reorder the terms:
(-2 + 4y) + -1(2y + 3) + (-2 + 4) = 0

Remove parenthesis around (-2 + 4y)
-2 + 4y + -1(2y + 3) + (-2 + 4) = 0

Reorder the terms:
-2 + 4y + -1(3 + 2y) + (-2 + 4) = 0
-2 + 4y + (3 * -1 + 2y * -1) + (-2 + 4) = 0
-2 + 4y + (-3 + -2y) + (-2 + 4) = 0

Combine like terms: -2 + 4 = 2
-2 + 4y + -3 + -2y + (2) = 0
-2 + 4y + -3 + -2y + 2 = 0

Reorder the terms:
-2 + -3 + 2 + 4y + -2y = 0

Combine like terms: -2 + -3 = -5
-5 + 2 + 4y + -2y = 0

Combine like terms: -5 + 2 = -3
-3 + 4y + -2y = 0

Combine like terms: 4y + -2y = 2y
-3 + 2y = 0

Solving
-3 + 2y = 0

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '3' to each side of the equation.
-3 + 3 + 2y = 0 + 3

Combine like terms: -3 + 3 = 0
0 + 2y = 0 + 3
2y = 0 + 3

Combine like terms: 0 + 3 = 3
2y = 3

Divide each side by '2'.
y = 1.5

Simplifying
y = 1.5

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