(4y-11)=(2y+13)

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Solution for (4y-11)=(2y+13) equation: 



(4y-11)=(2y+13)

We move all terms to the left:

(4y-11)-((2y+13))=0

We get rid of parentheses

4y-((2y+13))-11=0



We calculate terms in parentheses: -((2y+13)), so:

(2y+13)

We get rid of parentheses

2y+13

Back to the equation:

-(2y+13)



We get rid of parentheses

4y-2y-13-11=0

We add all the numbers together, and all the variables

2y-24=0

We move all terms containing y to the left, all other terms to the right

2y=24

y=24/2

y=12

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