(4y+8)-(2y-5)=2y+13

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Solution for (4y+8)-(2y-5)=2y+13 equation: 


Simplifying
(4y + 8) + -1(2y + -5) = 2y + 13

Reorder the terms:
(8 + 4y) + -1(2y + -5) = 2y + 13

Remove parenthesis around (8 + 4y)
8 + 4y + -1(2y + -5) = 2y + 13

Reorder the terms:
8 + 4y + -1(-5 + 2y) = 2y + 13
8 + 4y + (-5 * -1 + 2y * -1) = 2y + 13
8 + 4y + (5 + -2y) = 2y + 13

Reorder the terms:
8 + 5 + 4y + -2y = 2y + 13

Combine like terms: 8 + 5 = 13
13 + 4y + -2y = 2y + 13

Combine like terms: 4y + -2y = 2y
13 + 2y = 2y + 13

Reorder the terms:
13 + 2y = 13 + 2y

Add '-13' to each side of the equation.
13 + -13 + 2y = 13 + -13 + 2y

Combine like terms: 13 + -13 = 0
0 + 2y = 13 + -13 + 2y
2y = 13 + -13 + 2y

Combine like terms: 13 + -13 = 0
2y = 0 + 2y
2y = 2y

Add '-2y' to each side of the equation.
2y + -2y = 2y + -2y

Combine like terms: 2y + -2y = 0
0 = 2y + -2y

Combine like terms: 2y + -2y = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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