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(4y+5)+(3y-3)+(2y)+(y-2)=360
We move all terms to the left:
(4y+5)+(3y-3)+(2y)+(y-2)-(360)=0
We add all the numbers together, and all the variables
2y+(4y+5)+(3y-3)+(y-2)-360=0
We get rid of parentheses
2y+4y+3y+y+5-3-2-360=0
We add all the numbers together, and all the variables
10y-360=0
We move all terms containing y to the left, all other terms to the right
10y=360
y=360/10
y=36
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