(4y+3x)dy+(y-2x)=0

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Solution for (4y+3x)dy+(y-2x)=0 equation:


Simplifying
(4y + 3x) * dy + (y + -2x) = 0

Reorder the terms:
(3x + 4y) * dy + (y + -2x) = 0

Reorder the terms for easier multiplication:
dy(3x + 4y) + (y + -2x) = 0
(3x * dy + 4y * dy) + (y + -2x) = 0
(3dxy + 4dy2) + (y + -2x) = 0

Reorder the terms:
3dxy + 4dy2 + (-2x + y) = 0

Remove parenthesis around (-2x + y)
3dxy + 4dy2 + -2x + y = 0

Solving
3dxy + 4dy2 + -2x + y = 0

Solving for variable 'd'.

Move all terms containing d to the left, all other terms to the right.

Add '2x' to each side of the equation.
3dxy + 4dy2 + -2x + 2x + y = 0 + 2x

Combine like terms: -2x + 2x = 0
3dxy + 4dy2 + 0 + y = 0 + 2x
3dxy + 4dy2 + y = 0 + 2x
Remove the zero:
3dxy + 4dy2 + y = 2x

Add '-1y' to each side of the equation.
3dxy + 4dy2 + y + -1y = 2x + -1y

Combine like terms: y + -1y = 0
3dxy + 4dy2 + 0 = 2x + -1y
3dxy + 4dy2 = 2x + -1y

Reorder the terms:
3dxy + 4dy2 + -2x + y = 2x + -2x + -1y + y

Combine like terms: 2x + -2x = 0
3dxy + 4dy2 + -2x + y = 0 + -1y + y
3dxy + 4dy2 + -2x + y = -1y + y

Combine like terms: -1y + y = 0
3dxy + 4dy2 + -2x + y = 0

The solution to this equation could not be determined.

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