(4y+3)=-(3y+5)

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Solution for (4y+3)=-(3y+5) equation: 



(4y+3)=-(3y+5)

We move all terms to the left:

(4y+3)-(-(3y+5))=0

We get rid of parentheses

4y-(-(3y+5))+3=0



We calculate terms in parentheses: -(-(3y+5)), so:

-(3y+5)

We get rid of parentheses

-3y-5

Back to the equation:

-(-3y-5)



We get rid of parentheses

4y+3y+5+3=0

We add all the numbers together, and all the variables

7y+8=0

We move all terms containing y to the left, all other terms to the right

7y=-8

y=-8/7

y=-1+1/7

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