(4y+3)=(5y-1)

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Solution for (4y+3)=(5y-1) equation: 



(4y+3)=(5y-1)

We move all terms to the left:

(4y+3)-((5y-1))=0

We get rid of parentheses

4y-((5y-1))+3=0



We calculate terms in parentheses: -((5y-1)), so:

(5y-1)

We get rid of parentheses

5y-1

Back to the equation:

-(5y-1)



We get rid of parentheses

4y-5y+1+3=0

We add all the numbers together, and all the variables

-1y+4=0

We move all terms containing y to the left, all other terms to the right

-y=-4

y=-4/-1

y=+4

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