(4y+2)-(3y-4)=15

Solution for (4y+2)-(3y-4)=15 equation:

Simplifying
(4y + 2) + -1(3y + -4) = 15

Reorder the terms:
(2 + 4y) + -1(3y + -4) = 15

Remove parenthesis around (2 + 4y)
2 + 4y + -1(3y + -4) = 15

Reorder the terms:
2 + 4y + -1(-4 + 3y) = 15
2 + 4y + (-4 * -1 + 3y * -1) = 15
2 + 4y + (4 + -3y) = 15

Reorder the terms:
2 + 4 + 4y + -3y = 15

Combine like terms: 2 + 4 = 6
6 + 4y + -3y = 15

Combine like terms: 4y + -3y = 1y
6 + 1y = 15

Solving
6 + 1y = 15

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-6' to each side of the equation.
6 + -6 + 1y = 15 + -6

Combine like terms: 6 + -6 = 0
0 + 1y = 15 + -6
1y = 15 + -6

Combine like terms: 15 + -6 = 9
1y = 9

Divide each side by '1'.
y = 9

Simplifying
y = 9