(4y)=(5y-30)

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Solution for (4y)=(5y-30) equation: 



(4y)=(5y-30)

We move all terms to the left:

(4y)-((5y-30))=0



We calculate terms in parentheses: -((5y-30)), so:

(5y-30)

We get rid of parentheses

5y-30

Back to the equation:

-(5y-30)



We get rid of parentheses

4y-5y+30=0

We add all the numbers together, and all the variables

-1y+30=0

We move all terms containing y to the left, all other terms to the right

-y=-30

y=-30/-1

y=+30

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