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(4x=36)+(3x-3)=60
We move all terms to the left:
(4x-(36)+(3x-3))=0
We calculate terms in parentheses: +(4x-36+(3x-3)), so:We get rid of parentheses
4x-36+(3x-3)
determiningTheFunctionDomain 4x+(3x-3)-36
We get rid of parentheses
4x+3x-3-36
We add all the numbers together, and all the variables
7x-39
Back to the equation:
+(7x-39)
7x-39=0
We move all terms containing x to the left, all other terms to the right
7x=39
x=39/7
x=5+4/7
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