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(4x-9)(3x+29)=180
We move all terms to the left:
(4x-9)(3x+29)-(180)=0
We multiply parentheses ..
(+12x^2+116x-27x-261)-180=0
We get rid of parentheses
12x^2+116x-27x-261-180=0
We add all the numbers together, and all the variables
12x^2+89x-441=0
a = 12; b = 89; c = -441;
Δ = b2-4ac
Δ = 892-4·12·(-441)
Δ = 29089
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(89)-\sqrt{29089}}{2*12}=\frac{-89-\sqrt{29089}}{24} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(89)+\sqrt{29089}}{2*12}=\frac{-89+\sqrt{29089}}{24} $
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