(4x-84)+(x+24)+(1/2x+42=180

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Solution for (4x-84)+(x+24)+(1/2x+42=180 equation: 



(4x-84)+(x+24)+(1/2x+42=180

We move all terms to the left:

(4x-84)+(x+24)+(1/2x+42-(180)=0



Domain of the equation: 2x+42-180!=0

We move all terms containing x to the left, all other terms to the right

2x!=138

x!=138/2

x!=69

x∈R



We get rid of parentheses

4x+x+(1/2x+42-180-84+24=0

We multiply all the terms by the denominator


4x*2x+x*2x+42-180-84+24+42-180-84+24+(1=0

We add all the numbers together, and all the variables

4x*2x+x*2x=0

Wy multiply elements

8x^2+2x^2=0

We add all the numbers together, and all the variables

10x^2=0

a = 10; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·10·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{20}=0$

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