(4x-8)/4=(2x+3)/3

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Solution for (4x-8)/4=(2x+3)/3 equation: 



(4x-8)/4=(2x+3)/3

We move all terms to the left:

(4x-8)/4-((2x+3)/3)=0

We calculate fractions


4x/()+(-((2x+3)*4)/()=0



We calculate terms in parentheses: +(-((2x+3)*4)/(), so:

-((2x+3)*4)/(

We multiply all the terms by the denominator


-((2x+3)*4)



We calculate terms in parentheses: -((2x+3)*4), so:

(2x+3)*4

We multiply parentheses

8x+12

Back to the equation:

-(8x+12)



We get rid of parentheses

-8x-12

Back to the equation:

+(-8x-12)



We get rid of parentheses

4x/()-8x-12=0

We multiply all the terms by the denominator


4x-8x*()-12*()=0

We add all the numbers together, and all the variables

4x-8x*()=0

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