(4x-8)(2x+6)=0

Solution for (4x-8)(2x+6)=0 equation:

(4x-8)(2x+6)=0

We multiply parentheses ..

(+8x^2+24x-16x-48)=0

We get rid of parentheses

8x^2+24x-16x-48=0

We add all the numbers together, and all the variables

8x^2+8x-48=0

a = 8; b = 8; c = -48;
Δ = b2-4ac
Δ = 82-4·8·(-48)
Δ = 1600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1600}=40$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-40}{2*8}=\frac{-48}{16}
=-3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+40}{2*8}=\frac{32}{16}
=2
$