(4x-7)+(4x-7)=(10x-22)

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Solution for (4x-7)+(4x-7)=(10x-22) equation: 



(4x-7)+(4x-7)=(10x-22)

We move all terms to the left:

(4x-7)+(4x-7)-((10x-22))=0

We get rid of parentheses

4x+4x-((10x-22))-7-7=0



We calculate terms in parentheses: -((10x-22)), so:

(10x-22)

We get rid of parentheses

10x-22

Back to the equation:

-(10x-22)



We add all the numbers together, and all the variables

8x-(10x-22)-14=0

We get rid of parentheses

8x-10x+22-14=0

We add all the numbers together, and all the variables

-2x+8=0

We move all terms containing x to the left, all other terms to the right

-2x=-8

x=-8/-2

x=+4

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