(4x-7)(x+6)=0

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Solution for (4x-7)(x+6)=0 equation:



(4x-7)(x+6)=0
We multiply parentheses ..
(+4x^2+24x-7x-42)=0
We get rid of parentheses
4x^2+24x-7x-42=0
We add all the numbers together, and all the variables
4x^2+17x-42=0
a = 4; b = 17; c = -42;
Δ = b2-4ac
Δ = 172-4·4·(-42)
Δ = 961
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{961}=31$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(17)-31}{2*4}=\frac{-48}{8} =-6 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(17)+31}{2*4}=\frac{14}{8} =1+3/4 $

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