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(4x-7)(2x+2)=0
We multiply parentheses ..
(+8x^2+8x-14x-14)=0
We get rid of parentheses
8x^2+8x-14x-14=0
We add all the numbers together, and all the variables
8x^2-6x-14=0
a = 8; b = -6; c = -14;
Δ = b2-4ac
Δ = -62-4·8·(-14)
Δ = 484
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{484}=22$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-22}{2*8}=\frac{-16}{16} =-1 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+22}{2*8}=\frac{28}{16} =1+3/4 $
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