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(4x-6)=(2x^2+4x-3)
We move all terms to the left:
(4x-6)-((2x^2+4x-3))=0
We get rid of parentheses
4x-((2x^2+4x-3))-6=0
We calculate terms in parentheses: -((2x^2+4x-3)), so:We get rid of parentheses
(2x^2+4x-3)
We get rid of parentheses
2x^2+4x-3
Back to the equation:
-(2x^2+4x-3)
-2x^2+4x-4x+3-6=0
We add all the numbers together, and all the variables
-2x^2-3=0
a = -2; b = 0; c = -3;
Δ = b2-4ac
Δ = 02-4·(-2)·(-3)
Δ = -24
Delta is less than zero, so there is no solution for the equation
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