(4x-6)+(3x-1)=35

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Solution for (4x-6)+(3x-1)=35 equation: 



(4x-6)+(3x-1)=35

We move all terms to the left:

(4x-6)+(3x-1)-(35)=0

We get rid of parentheses

4x+3x-6-1-35=0

We add all the numbers together, and all the variables

7x-42=0

We move all terms containing x to the left, all other terms to the right

7x=42

x=42/7

x=6

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