(4x-52)+(x+16)+(180-(7x-106))=180

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Solution for (4x-52)+(x+16)+(180-(7x-106))=180 equation: 



(4x-52)+(x+16)+(180-(7x-106))=180

We move all terms to the left:

(4x-52)+(x+16)+(180-(7x-106))-(180)=0

We get rid of parentheses

4x+x+(180-(7x-106))-52+16-180=0



We calculate terms in parentheses: +(180-(7x-106)), so:

180-(7x-106)

determiningTheFunctionDomain
-(7x-106)+180

We get rid of parentheses

-7x+106+180

We add all the numbers together, and all the variables

-7x+286

Back to the equation:

+(-7x+286)



We add all the numbers together, and all the variables

5x+(-7x+286)-216=0

We get rid of parentheses

5x-7x+286-216=0

We add all the numbers together, and all the variables

-2x+70=0

We move all terms containing x to the left, all other terms to the right

-2x=-70

x=-70/-2

x=+35

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