(4x-5)/6=(3x+4)/5

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Solution for (4x-5)/6=(3x+4)/5 equation: 



(4x-5)/6=(3x+4)/5

We move all terms to the left:

(4x-5)/6-((3x+4)/5)=0

We calculate fractions


4x/()+(-((3x+4)*6)/()=0



We calculate terms in parentheses: +(-((3x+4)*6)/(), so:

-((3x+4)*6)/(

We multiply all the terms by the denominator


-((3x+4)*6)



We calculate terms in parentheses: -((3x+4)*6), so:

(3x+4)*6

We multiply parentheses

18x+24

Back to the equation:

-(18x+24)



We get rid of parentheses

-18x-24

Back to the equation:

+(-18x-24)



We get rid of parentheses

4x/()-18x-24=0

We multiply all the terms by the denominator


4x-18x*()-24*()=0

We add all the numbers together, and all the variables

4x-18x*()=0

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