(4x-5)+(8x-42)=61

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Solution for (4x-5)+(8x-42)=61 equation: 



(4x-5)+(8x-42)=61

We move all terms to the left:

(4x-5)+(8x-42)-(61)=0

We get rid of parentheses

4x+8x-5-42-61=0

We add all the numbers together, and all the variables

12x-108=0

We move all terms containing x to the left, all other terms to the right

12x=108

x=108/12

x=9

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