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(4x-5)(5x+5)=0
We multiply parentheses ..
(+20x^2+20x-25x-25)=0
We get rid of parentheses
20x^2+20x-25x-25=0
We add all the numbers together, and all the variables
20x^2-5x-25=0
a = 20; b = -5; c = -25;
Δ = b2-4ac
Δ = -52-4·20·(-25)
Δ = 2025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2025}=45$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-45}{2*20}=\frac{-40}{40} =-1 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+45}{2*20}=\frac{50}{40} =1+1/4 $
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