(4x-5)(3x+8)=12x2+57

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Solution for (4x-5)(3x+8)=12x2+57 equation: 



(4x-5)(3x+8)=12x^2+57

We move all terms to the left:

(4x-5)(3x+8)-(12x^2+57)=0

We get rid of parentheses

-12x^2+(4x-5)(3x+8)-57=0

We multiply parentheses ..

-12x^2+(+12x^2+32x-15x-40)-57=0

We get rid of parentheses

-12x^2+12x^2+32x-15x-40-57=0

We add all the numbers together, and all the variables

17x-97=0

We move all terms containing x to the left, all other terms to the right

17x=97

x=97/17

x=5+12/17

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