(4x-4)=(-3x+53)

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Solution for (4x-4)=(-3x+53) equation: 



(4x-4)=(-3x+53)

We move all terms to the left:

(4x-4)-((-3x+53))=0

We get rid of parentheses

4x-((-3x+53))-4=0



We calculate terms in parentheses: -((-3x+53)), so:

(-3x+53)

We get rid of parentheses

-3x+53

Back to the equation:

-(-3x+53)



We get rid of parentheses

4x+3x-53-4=0

We add all the numbers together, and all the variables

7x-57=0

We move all terms containing x to the left, all other terms to the right

7x=57

x=57/7

x=8+1/7

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