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(4x-4)(0.5x+32)=80
We move all terms to the left:
(4x-4)(0.5x+32)-(80)=0
We multiply parentheses ..
(+0x^2+128x+0x-128)-80=0
We get rid of parentheses
0x^2+128x+0x-128-80=0
We add all the numbers together, and all the variables
x^2+129x-208=0
a = 1; b = 129; c = -208;
Δ = b2-4ac
Δ = 1292-4·1·(-208)
Δ = 17473
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(129)-\sqrt{17473}}{2*1}=\frac{-129-\sqrt{17473}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(129)+\sqrt{17473}}{2*1}=\frac{-129+\sqrt{17473}}{2} $
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