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(4x-3=3x+2)
We move all terms to the left:
(4x-3-(3x+2))=0
We calculate terms in parentheses: +(4x-3-(3x+2)), so:We get rid of parentheses
4x-3-(3x+2)
determiningTheFunctionDomain 4x-(3x+2)-3
We get rid of parentheses
4x-3x-2-3
We add all the numbers together, and all the variables
x-5
Back to the equation:
+(x-5)
x-5=0
We move all terms containing x to the left, all other terms to the right
x=5
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