(4x-3)2=(x-7)2

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Solution for (4x-3)2=(x-7)2 equation: 



(4x-3)2=(x-7)2

We move all terms to the left:

(4x-3)2-((x-7)2)=0

We multiply parentheses

8x-((x-7)2)-6=0



We calculate terms in parentheses: -((x-7)2), so:

(x-7)2

We multiply parentheses

2x-14

Back to the equation:

-(2x-14)



We get rid of parentheses

8x-2x+14-6=0

We add all the numbers together, and all the variables

6x+8=0

We move all terms containing x to the left, all other terms to the right

6x=-8

x=-8/6

x=-1+1/3

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