(4x-3)/4=(x-18)/2

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Solution for (4x-3)/4=(x-18)/2 equation: 



(4x-3)/4=(x-18)/2

We move all terms to the left:

(4x-3)/4-((x-18)/2)=0

We calculate fractions


4x/()+(-((x-18)*4)/()=0



We calculate terms in parentheses: +(-((x-18)*4)/(), so:

-((x-18)*4)/(

We multiply all the terms by the denominator


-((x-18)*4)



We calculate terms in parentheses: -((x-18)*4), so:

(x-18)*4

We multiply parentheses

4x-72

Back to the equation:

-(4x-72)



We get rid of parentheses

-4x+72

Back to the equation:

+(-4x+72)



We get rid of parentheses

4x/()-4x+72=0

We multiply all the terms by the denominator


4x-4x*()+72*()=0

We add all the numbers together, and all the variables

4x-4x*()=0

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