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(4x-3)/(2x-1)=10
We move all terms to the left:
(4x-3)/(2x-1)-(10)=0
Domain of the equation: (2x-1)!=0We multiply all the terms by the denominator
We move all terms containing x to the left, all other terms to the right
2x!=1
x!=1/2
x!=1/2
x∈R
(4x-3)-10*(2x-1)=0
We multiply parentheses
(4x-3)-20x+10=0
We get rid of parentheses
4x-20x-3+10=0
We add all the numbers together, and all the variables
-16x+7=0
We move all terms containing x to the left, all other terms to the right
-16x=-7
x=-7/-16
x=7/16
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