(4x-3)(3-2x)+(8x-1)(x+3)=4(x-13)+3

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Solution for (4x-3)(3-2x)+(8x-1)(x+3)=4(x-13)+3 equation:



(4x-3)(3-2x)+(8x-1)(x+3)=4(x-13)+3
We move all terms to the left:
(4x-3)(3-2x)+(8x-1)(x+3)-(4(x-13)+3)=0
We add all the numbers together, and all the variables
(4x-3)(-2x+3)+(8x-1)(x+3)-(4(x-13)+3)=0
We multiply parentheses ..
(-8x^2+12x+6x-9)+(8x-1)(x+3)-(4(x-13)+3)=0
We calculate terms in parentheses: -(4(x-13)+3), so:
4(x-13)+3
We multiply parentheses
4x-52+3
We add all the numbers together, and all the variables
4x-49
Back to the equation:
-(4x-49)
We get rid of parentheses
-8x^2+12x+6x+(8x-1)(x+3)-4x-9+49=0
We multiply parentheses ..
-8x^2+(+8x^2+24x-1x-3)+12x+6x-4x-9+49=0
We add all the numbers together, and all the variables
-8x^2+(+8x^2+24x-1x-3)+14x+40=0
We get rid of parentheses
-8x^2+8x^2+24x-1x+14x-3+40=0
We add all the numbers together, and all the variables
37x+37=0
We move all terms containing x to the left, all other terms to the right
37x=-37
x=-37/37
x=-1

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