(4x-3)(2x+6)+(3x-4)(2x+6)=(7x+4)(2x-5)

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Solution for (4x-3)(2x+6)+(3x-4)(2x+6)=(7x+4)(2x-5) equation:



(4x-3)(2x+6)+(3x-4)(2x+6)=(7x+4)(2x-5)
We move all terms to the left:
(4x-3)(2x+6)+(3x-4)(2x+6)-((7x+4)(2x-5))=0
We multiply parentheses ..
(+8x^2+24x-6x-18)+(3x-4)(2x+6)-((7x+4)(2x-5))=0
We calculate terms in parentheses: -((7x+4)(2x-5)), so:
(7x+4)(2x-5)
We multiply parentheses ..
(+14x^2-35x+8x-20)
We get rid of parentheses
14x^2-35x+8x-20
We add all the numbers together, and all the variables
14x^2-27x-20
Back to the equation:
-(14x^2-27x-20)
We get rid of parentheses
8x^2-14x^2+24x-6x+(3x-4)(2x+6)+27x-18+20=0
We multiply parentheses ..
8x^2-14x^2+(+6x^2+18x-8x-24)+24x-6x+27x-18+20=0
We add all the numbers together, and all the variables
-6x^2+(+6x^2+18x-8x-24)+45x+2=0
We get rid of parentheses
-6x^2+6x^2+18x-8x+45x-24+2=0
We add all the numbers together, and all the variables
55x-22=0
We move all terms containing x to the left, all other terms to the right
55x=22
x=22/55
x=2/5

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