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(4x-3)(2x+5)-11=20x-4(2x+1)(2-x)+6
We move all terms to the left:
(4x-3)(2x+5)-11-(20x-4(2x+1)(2-x)+6)=0
We add all the numbers together, and all the variables
(4x-3)(2x+5)-(20x-4(2x+1)(-1x+2)+6)-11=0
We multiply parentheses ..
(+8x^2+20x-6x-15)-(20x-4(2x+1)(-1x+2)+6)-11=0
We calculate terms in parentheses: -(20x-4(2x+1)(-1x+2)+6), so:We get rid of parentheses
20x-4(2x+1)(-1x+2)+6
We multiply parentheses ..
-4(-2x^2+4x-1x+2)+20x+6
We multiply parentheses
8x^2-16x+4x+20x-8+6
We add all the numbers together, and all the variables
8x^2+8x-2
Back to the equation:
-(8x^2+8x-2)
8x^2-8x^2+20x-6x-8x-15+2-11=0
We add all the numbers together, and all the variables
6x-24=0
We move all terms containing x to the left, all other terms to the right
6x=24
x=24/6
x=4
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