(4x-3)(2x+2)-(8x+2)(x+3)=0

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Solution for (4x-3)(2x+2)-(8x+2)(x+3)=0 equation:



(4x-3)(2x+2)-(8x+2)(x+3)=0
We multiply parentheses ..
(+8x^2+8x-6x-6)-(8x+2)(x+3)=0
We get rid of parentheses
8x^2+8x-6x-(8x+2)(x+3)-6=0
We multiply parentheses ..
8x^2-(+8x^2+24x+2x+6)+8x-6x-6=0
We add all the numbers together, and all the variables
8x^2-(+8x^2+24x+2x+6)+2x-6=0
We get rid of parentheses
8x^2-8x^2-24x-2x+2x-6-6=0
We add all the numbers together, and all the variables
-24x-12=0
We move all terms containing x to the left, all other terms to the right
-24x=12
x=12/-24
x=-1/2

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