(4x-23)+(98-2x)+(4x+27)=180

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Solution for (4x-23)+(98-2x)+(4x+27)=180 equation: 



(4x-23)+(98-2x)+(4x+27)=180

We move all terms to the left:

(4x-23)+(98-2x)+(4x+27)-(180)=0

We add all the numbers together, and all the variables

(4x-23)+(-2x+98)+(4x+27)-180=0

We get rid of parentheses

4x-2x+4x-23+98+27-180=0

We add all the numbers together, and all the variables

6x-78=0

We move all terms containing x to the left, all other terms to the right

6x=78

x=78/6

x=13

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