(4x-2)/3=(4x+2)/5

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Solution for (4x-2)/3=(4x+2)/5 equation: 



(4x-2)/3=(4x+2)/5

We move all terms to the left:

(4x-2)/3-((4x+2)/5)=0

We calculate fractions


4x/()+(-((4x+2)*3)/()=0



We calculate terms in parentheses: +(-((4x+2)*3)/(), so:

-((4x+2)*3)/(

We multiply all the terms by the denominator


-((4x+2)*3)



We calculate terms in parentheses: -((4x+2)*3), so:

(4x+2)*3

We multiply parentheses

12x+6

Back to the equation:

-(12x+6)



We get rid of parentheses

-12x-6

Back to the equation:

+(-12x-6)



We get rid of parentheses

4x/()-12x-6=0

We multiply all the terms by the denominator


4x-12x*()-6*()=0

We add all the numbers together, and all the variables

4x-12x*()=0

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