(4x-2)+16x=2(4x+2)+16

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Solution for (4x-2)+16x=2(4x+2)+16 equation: 



(4x-2)+16x=2(4x+2)+16

We move all terms to the left:

(4x-2)+16x-(2(4x+2)+16)=0

We add all the numbers together, and all the variables

16x+(4x-2)-(2(4x+2)+16)=0

We get rid of parentheses

16x+4x-(2(4x+2)+16)-2=0



We calculate terms in parentheses: -(2(4x+2)+16), so:

2(4x+2)+16

We multiply parentheses

8x+4+16

We add all the numbers together, and all the variables

8x+20

Back to the equation:

-(8x+20)



We add all the numbers together, and all the variables

20x-(8x+20)-2=0

We get rid of parentheses

20x-8x-20-2=0

We add all the numbers together, and all the variables

12x-22=0

We move all terms containing x to the left, all other terms to the right

12x=22

x=22/12

x=1+5/6

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