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(4x-2)(2x+4)=0
We multiply parentheses ..
(+8x^2+16x-4x-8)=0
We get rid of parentheses
8x^2+16x-4x-8=0
We add all the numbers together, and all the variables
8x^2+12x-8=0
a = 8; b = 12; c = -8;
Δ = b2-4ac
Δ = 122-4·8·(-8)
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{400}=20$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-20}{2*8}=\frac{-32}{16} =-2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+20}{2*8}=\frac{8}{16} =1/2 $
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