(4x-2)(11x+17)=1810

Solution for (4x-2)(11x+17)=1810 equation:

(4x-2)(11x+17)=1810

We move all terms to the left:

(4x-2)(11x+17)-(1810)=0

We multiply parentheses ..

(+44x^2+68x-22x-34)-1810=0

We get rid of parentheses

44x^2+68x-22x-34-1810=0

We add all the numbers together, and all the variables

44x^2+46x-1844=0

a = 44; b = 46; c = -1844;
Δ = b2-4ac
Δ = 462-4·44·(-1844)
Δ = 326660
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{326660}=\sqrt{4*81665}=\sqrt{4}*\sqrt{81665}=2\sqrt{81665}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(46)-2\sqrt{81665}}{2*44}=\frac{-46-2\sqrt{81665}}{88}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(46)+2\sqrt{81665}}{2*44}=\frac{-46+2\sqrt{81665}}{88}
$