(4x-18)=(2x+6)+36=

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Solution for (4x-18)=(2x+6)+36= equation: 



(4x-18)=(2x+6)+36=

We move all terms to the left:

(4x-18)-((2x+6)+36)=0

We get rid of parentheses

4x-((2x+6)+36)-18=0



We calculate terms in parentheses: -((2x+6)+36), so:

(2x+6)+36

We get rid of parentheses

2x+6+36

We add all the numbers together, and all the variables

2x+42

Back to the equation:

-(2x+42)



We get rid of parentheses

4x-2x-42-18=0

We add all the numbers together, and all the variables

2x-60=0

We move all terms containing x to the left, all other terms to the right

2x=60

x=60/2

x=30

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