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(4x-15)*3x=90
We move all terms to the left:
(4x-15)*3x-(90)=0
We multiply parentheses
12x^2-45x-90=0
a = 12; b = -45; c = -90;
Δ = b2-4ac
Δ = -452-4·12·(-90)
Δ = 6345
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{6345}=\sqrt{9*705}=\sqrt{9}*\sqrt{705}=3\sqrt{705}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-45)-3\sqrt{705}}{2*12}=\frac{45-3\sqrt{705}}{24} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-45)+3\sqrt{705}}{2*12}=\frac{45+3\sqrt{705}}{24} $
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