(4x-12)=(7x-28)

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Solution for (4x-12)=(7x-28) equation: 



(4x-12)=(7x-28)

We move all terms to the left:

(4x-12)-((7x-28))=0

We get rid of parentheses

4x-((7x-28))-12=0



We calculate terms in parentheses: -((7x-28)), so:

(7x-28)

We get rid of parentheses

7x-28

Back to the equation:

-(7x-28)



We get rid of parentheses

4x-7x+28-12=0

We add all the numbers together, and all the variables

-3x+16=0

We move all terms containing x to the left, all other terms to the right

-3x=-16

x=-16/-3

x=5+1/3

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