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(4x-12)-3(x+2)=3
We move all terms to the left:
(4x-12)-3(x+2)-(3)=0
We multiply parentheses
(4x-12)-3x-6-3=0
We get rid of parentheses
4x-3x-12-6-3=0
We add all the numbers together, and all the variables
x-21=0
We move all terms containing x to the left, all other terms to the right
x=21
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