(4x-12)+(3x+4)+(x)=180

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Solution for (4x-12)+(3x+4)+(x)=180 equation: 



(4x-12)+(3x+4)+(x)=180

We move all terms to the left:

(4x-12)+(3x+4)+(x)-(180)=0

We add all the numbers together, and all the variables

x+(4x-12)+(3x+4)-180=0

We get rid of parentheses

x+4x+3x-12+4-180=0

We add all the numbers together, and all the variables

8x-188=0

We move all terms containing x to the left, all other terms to the right

8x=188

x=188/8

x=23+1/2

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