(4x-100)+(x+20)+((1/5x)+2)=180

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Solution for (4x-100)+(x+20)+((1/5x)+2)=180 equation: 



(4x-100)+(x+20)+((1/5x)+2)=180

We move all terms to the left:

(4x-100)+(x+20)+((1/5x)+2)-(180)=0



Domain of the equation: 5x)+2)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

(4x-100)+(x+20)+((+1/5x)+2)-180=0

We get rid of parentheses

4x+x+((+1/5x)+2)-100+20-180=0

We multiply all the terms by the denominator


4x*5x)+2)+x*5x)+2)+((+1-100*5x)+2)+20*5x)+2)-180*5x)+2)=0

We add all the numbers together, and all the variables

4x*5x)+2)+x*5x)+2)+((-100*5x+1)+2)+20*5x)+2)-180*5x)+2)=0

Wy multiply elements

12500x^6=0

We do not support expression: x^6

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