(4x-10)=(2x+52)=132

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Solution for (4x-10)=(2x+52)=132 equation: 



(4x-10)=(2x+52)=132

We move all terms to the left:

(4x-10)-((2x+52))=0

We get rid of parentheses

4x-((2x+52))-10=0



We calculate terms in parentheses: -((2x+52)), so:

(2x+52)

We get rid of parentheses

2x+52

Back to the equation:

-(2x+52)



We get rid of parentheses

4x-2x-52-10=0

We add all the numbers together, and all the variables

2x-62=0

We move all terms containing x to the left, all other terms to the right

2x=62

x=62/2

x=31

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